数论中的一个关键结果是:如果素数 p 能整除两个整数 a 和 b 的乘积,那么 p 必定能整除这两个整数中的至少一个。也就是说,如果 p 整除 ab,那么 p 整除 a 或 p 整除 b。这个性质对于证明基本定理的唯一性部分至关重要。 算术定理.

(图片仅供参考)
数论中的一个关键结果是:如果素数 p 能整除两个整数 a 和 b 的乘积,那么 p 必定能整除这两个整数中的至少一个。也就是说,如果 p 整除 ab,那么 p 整除 a 或 p 整除 b。这个性质对于证明基本定理的唯一性部分至关重要。 算术定理.
Euclid’s Lemma is Proposition 30 in Book VII of his *Elements*. Its proof typically relies on another fundamental result, Bézout’s identity, which states that the greatest common divisor (GCD) of two integers `a` and `b` can be expressed as a linear combination `ax + by` for some integers `x` and `y`. The proof of the lemma proceeds as follows: Assume a prime `p` divides `ab`. If `p` does not divide `a`, then `p` and `a` are coprime (their GCD is 1), since the only divisors of `p` are 1 and `p`. By Bézout’s identity, there exist integers `x` and `y` such that `px + ay = 1`. Multiplying this entire equation by `b` gives `pbx + aby = b`. We know that `p` divides `pbx` (trivially) and `p` divides `aby` (by our initial assumption that `p` divides `ab`). Therefore, `p` must divide their sum, which is `b`. This completes the proof.
This lemma is the critical step in establishing the uniqueness of prime factorizations. Without it, one could potentially have two different sets of prime factors for the same number. The lemma ensures that if a prime appears in one factorization, it must also appear in any other factorization of the same number. The property described in the lemma is now used to define the more general concept of a ‘prime element’ in abstract algebra and ring theory, distinguishing it from an ‘irreducible element’.
欧氏定理
(如果日期未知或不相关,例如“流体力学”,则提供其显著出现的近似估计)
只有注册会员才能免费获得 100% 的全尺寸图片和下载。.
> 登录 <